If 3 men or 5 women can finish a work in 43 days. Then in how many days 5 men and 6 women together do it ?
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1Please show your effort in solving this problem so that you can be helped. – Aditya Jain Jul 05 '19 at 10:49
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2Possible duplicate of Time and Work in Unitary Method – Aditya Jain Jul 05 '19 at 10:52
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aditiya jain its not the same question .. i think you did not read the question properly. – Ravi Kadyan Jul 05 '19 at 10:54
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1@RaviKadyan It is the same question and more of a hint than you deserve. If you would do your own work you might actually see that, – John Douma Jul 05 '19 at 10:56
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my question contain or not and that make a huge difference – Ravi Kadyan Jul 05 '19 at 10:58
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215 days! Because one woman is working and you can guess what the rest of the crew is doing! – David Jul 05 '19 at 11:04
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1@denklo Read the question again "3 men OR 5 women can finish a work in 43 days" – David Jul 05 '19 at 11:05
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Mark the answer which is the answer to your question. – Rajendra Singh Jul 05 '19 at 11:10
4 Answers
A man does $\frac{1}{3\times 43} = \frac1{129}$th of the job in one day, whereas a woman does $\frac{1}{5\times 43} = \frac{1}{215}$th of the job.
Working together, $5$ men and $6$ women do $$\frac{5}{129}+\frac{6}{215}=\frac{1}{15}\text{th}$$ of the job. Thus they require 15 days.
- 8,748
here the answer..
$3M=5W$
$1M=5/3W$
Then Formula of this $(Man1 * days * hours)/work=(man2 * days * hours )/work$
$5(5/3) + 6 +D = 5* 43$
$D=15$
- 134
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You have to give support instead of downvote. if you have a better answer post it. ask question raiser to mark as answer. – Rajendra Singh Jul 05 '19 at 11:26
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I did not downvote your answer, be sure ! I was just trying to make a joke. I upvote your answer and delete my comment since, obviously, you took it badly. This was not my intent. So, I really apologize. Cheers. – Claude Leibovici Jul 05 '19 at 11:38
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@JohnDouma. I was just trying to make a joke ! Comment deleted – Claude Leibovici Jul 05 '19 at 11:40
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@ Claude Leibovici Now it is alright, my mean was not like I took it badly. Cheers – Rajendra Singh Jul 05 '19 at 11:42
If $3$ men can finish a work in $43$ days, then $1$ man can finish a work in $43\times3=129$ days. so a man can finish $\frac{1}{129}$ of a work in a day.
If $5$ women can finish a work in $43$ days, then $1$ woman can finish a work in $43\times5=215$ days, so a woman can finish $\frac{1}{215}$ of a work in a day.
So, 5 men and 6 women can finish $\frac{1}{129}\times5+\frac{1}{215}\times6=\frac{1}{15}$ work in a day, so it requires $15$ days to finish the work with 5 men and 6 women.
- 2,785
Hint:
Let $a$ be the amount done by a man in one day and $b$ be the amount done by a woman in one day. Then if there are $d$ days and $m$ men and $w$ women, the total amount done $T$ is presumably $$T=d \left(am+bw\right)$$
You can calculate
- the value for $a$ when $T=1, d=43, m=3, w=0$
- the value for $b$ when $T=1, d=43, m=0, w=5$
and (assuming they do not change) use these to find
- the value for $d$ when $T=1, m=5, w=6$
- 157,058