The partition induces the relation $Q\subset B\times B$ in the following way. We say that $(x,y) \in Q$ (for $x,y\in B$) if there exists a set $S$ in your partition such that $x,y\in S$.
This is reflexive since trivially any element $x\in B$ is contained in some set of the partition by virtue of it being a partition and hence $(x,x)\in Q$, so we have reflexivity.
This is symmetric since if $(x,y)\in Q$ then by definition that means that there exists a set $S$ of the partition such that $x\in S$ and $y\in S$. But then $(y,x)\in Q$, so we have symmetry.
This is transitive since if $(x,y)\in Q$ and $(y,z)\in Q$ then we have that there exist sets $S$ and $T$ such that $x,y\in S$ and $y,z\in T$. But by definition of a partition, if $y\in S$ and $y\in T$ then $S=T$, so $x,z\in S$ and hence $(x,z)\in Q$, so we have transitivity.
OK, so now that we have made it clear exactly how a partition induces an equivalence relation, we may ask what the equivalence classes of this equivalence relations are. Well, we say that two elements $x,y\in B$ are in the same equivalence class $[x]=[y]$ if and only if $(x,y)\in Q$. But $(x,y)\in Q$ if and only if $x$ and $y$ are elements of the same set of the partition, and so the equivalence class of any element $[x]$ is just the set of the partition that it belongs to. Every set of the partition contains an element and hence maps into an equivalence class, and two elements belong to the same equivalence class iff they belong to the same set of the partition -- I hope this makes it clear, the equivalence classes are the sets of the partition.