Is there a coloring of $3$ colors on $\mathbb{R}^2$ such that every line contains exactly $2$ (different) colors and there is no triangle with unit area whose vertices lie on $3$ different colors? All points have to be colored. All $3$ colors have to be used.
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2Look up Monsky's theorem. This question appears to be intimately related to its proof.. – Paul Sinclair Aug 19 '19 at 22:56