How do i simplify this boolean expression with steps? I am so lost for some reason. I entered it into my logic converter on multisim and did recieve the simplified version.
A׳B׳C+A׳BC׳+AB׳C׳+ABC'
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Try kmap?....... – AgentS Aug 24 '19 at 15:52
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We havent learned them yet. I was put in this class because I scored high so I'm a bit behind in what they know va me and just looking for help. – Elijah W Aug 24 '19 at 16:03
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Ohk kmap is not necessary... Iet me grab a paper.:) – AgentS Aug 24 '19 at 16:05
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Okay thank you. I will try... I appreciate you:) – Elijah W Aug 24 '19 at 16:34
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$$A'B'C+A'BC'+AB'C'+ABC'$$
With out kmap, you just have to eyeball:
1) Last two terms have $AC'$ as common
2) $2$nd and last terms have $BC'$ as common
So group them like this:
$$A'B'C+(A'BC'+ABC')+(AB'C'+ABC')$$
Factor out the common and see if you can take it from there.
AgentS
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