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how exactly did he apply 1.39 to get

$$f(x-1)^2 =f(1-x)^2$$

SuperMage1
  • 2,486

1 Answers1

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It is not difficult; note that $$ f(x-1)^2=f((x-1)^2)=f((1-x)^2)=f(1-x)^2.$$