1

I have tried to evaluate the following sum:

$$\sum_{n\geq1}\frac{1}{n^3 \sin^2 n}$$ to test whether it is a convergent series using standard method like creterion test really I think that $ \sin^2 n$ Bounded sequence which is its multiplicative inverse multiplied by a convergent sequence , But my problem is about the Growth rate of :$\dfrac{1}{\sin^2 n}$ seems not clear to me , Now am not able to test the convergence of this series, anyway ?

StubbornAtom
  • 17,052
zeraoulia rafik
  • 7,055
  • 4
    It's expected to be convergent, but nobody knows at the moment. See here: https://mathoverflow.net/questions/24579/convergence-of-sumn3-sin2n-1 – Virtuoz Aug 31 '19 at 14:53
  • 5
    I'm voting to close this question because it is an exact duplicate, as noted by @GabrielRomon. The system will not allow us to close as a duplicate because the previous question did not get an answer (probably because it's still an open problem), but that doesn't make it any less a duplicate. – hmakholm left over Monica Aug 31 '19 at 15:21
  • I've flagged it for mod intervention as it is an exact duplicate and there's no hope for a way forward on this post beyond what was contained in the other linked. – Cameron Williams Aug 31 '19 at 15:21

0 Answers0