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From my calculation the fundamental period is $\frac{21\pi}{2 }$ is this correct?

Rishi
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Jhon22
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  • See Sin x repeats after $2\pi$.Since your x is now $21x$ ,it means period will be cut down 1/21 times. – Rishi Sep 04 '19 at 13:21

1 Answers1

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A general form is given by:

$$\text{a}\cdot\sin\left(\omega\cdot t+\varphi\right)\tag1$$

And we know that:

$$\omega=2\pi\text{f}=\frac{2\pi}{\text{T}}\tag2$$

So:

$$\text{a}\cdot\sin\left(\frac{2\pi}{\text{T}}\cdot t+\varphi\right)\tag3$$

So, the period is given by:

$$\text{T}=\frac{2\pi}{\omega}\tag4$$

you're not right!

Jan Eerland
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  • I used this formula \begin{align} {\frac{1}{f}} \end{align} Am I not allowed to use this formula in this case? – Jhon22 Sep 04 '19 at 13:35
  • This is how I calculated \begin{align} {ω}={21} \end{align}

    \begin{align} f={\frac{2π}{ω}} \end{align}

    \begin{align} T={\frac{1}{f}} \end{align}

     – Jhon22 Sep 04 '19 at 13:42