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this is the function:

$$\displaystyle f(a,b) = \frac{b^2}{4(1+a)}$$

M.H
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1 Answers1

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For quasi convexity you have to consider for $\alpha\in R$ the set $$\{(a,b)\in R^{2}: f(a,b)\leq \alpha\} $$ If this set is convex for every $\alpha \in R$ you have quasi convexity.

So we obtain the equality $$4(1+a)\leq \alpha b^{2}.$$

If you draw this set as set in $R^{2}$ for fixed $\alpha\in R$, this should give you a clue about quasi convexity...

Alex
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