Using the Euler-Poisson integral, prove the identity

Question

We have: $$I(a) =\int_{-\infty}^{+\infty}e^{-(ax^2+2bx)}dx $$ To prove: $$I(a) = \sqrt{\frac\pi a}e^{b^2/a}$$

I tried to differencate both sides, and got this:

Left side:

$$I'(a) = -2a\int_{-\infty}^{+\infty}xe^{-(ax^2+2bx)}dx -I(a)$$

Right side:

$$I'(a) = -I(a)\frac{b^2}{a^2}-I(a)\frac{1}{2a}$$

How about the substitution $y=\sqrt a(x+b/a)$? – Vasily Mitch Sep 17 '19 at 10:39 — Vasily Mitch, Sep 17 '19 at 10:39

score 2 · Accepted Answer · answered Sep 17 '19 at 10:39

2

Use $y=x+b/a$ so $I(a)=\int_{\Bbb R}e^{-ay^2+b^2/a}dy$, so the problem reduces to proving $\int_{\Bbb R}e^{-ay^2}dy=\sqrt{\frac{\pi}{a}}$. You can do the rest yourself (there are many ways to get $I(1)$, which is the crux of it).

answered Sep 17 '19 at 10:39

J.G.

115,835

score 1 · Answer 2 · answered Sep 17 '19 at 11:17

1

notice that: $$ax^2+2bx=\left(\sqrt{a}x+\frac{b}{\sqrt{a}}\right)^2-\frac{b^2}{a}$$ Then you can make the substitution $u=\sqrt{a}x+\frac{b}{\sqrt{a}}$ and it can then be easily defined using well known definitions

answered Sep 17 '19 at 11:17

Henry Lee

12,215

Using the Euler-Poisson integral, prove the identity

2 Answers2