An article was sold at 10% profit. Had it been purchased at Rs 22 more and sold at 5% more, the profit remains same. Find the SP to gain a profit of 62.5%?
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This has nothing to do with numerical linear algebra. Select appropriate tags for your questions to facilitate their solution. – Carl Christian Oct 04 '19 at 18:08
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Let the Cost Price (CP) be, $x$. Given profit $= 10\%$ , profit in amount = $10\%$ of $x$ $=\frac1{10}\cdot x$
Then CP become $x+22$ and profit is $5\%$ of CP $=$ $\frac{1}{20}\cdot (x+22)$. According to the question profit is same therefore
$\frac{1}{20}\cdot (x+22)=\frac1{10}\cdot x$
Now you get $x$ (CP)$= 22$. Can you take it from here?
Akshaj Bansal
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Let $c$ be the cost and establish the following relationship from the same profit,
$$10\%\>c = 105\% \cdot110\% \>c - (c+22)$$
Solve for the cost,
$$c = \frac{22}{105\% \cdot110\% - 10\% -1} = 400$$
Then, the selling price for 62.5% profit is 1.625$\times c$.
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