An empty container of length $12 \ \textrm{cm}$ and the vertical cross section of it is an isosceles right angled triangle.
If the water poured in it at a rate $\frac{10 \ \textrm{cm}}{\textrm{sec}}$ find the rate of change of height of water in the container when the depth of water is $2 \ \textrm{cm}$.
I´ve found that the volume of container $= 6 \cdot (\textrm{"side length of triangle"})^2$.
But I don't know how to continue ...
