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Show the following:

$\ $ (a) $\, \sum_{i=1}^n(3i+2n)\text{ is }O(n^2)$

$\ $ (b) $\, \sum_{k=1}^n(k/3)\text{ is }\Omega(n^2)$

$\ $ (c) $\, \sum_{j=1}^n\sum_{k=1}^n 7n\text{ is }\Theta(n^3)$.

Thank you.

1 Answers1

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The first sum can be separated, giving you $2n(n)+\sum_1^n 3i$, which gives you $2n^2+\frac32(n+1)n$. Clearly this is $\mathcal{O}(n^2)$. The rest are similarly straightforward.

Use the definitions.