Can somebody please help me simplify this expression using DeMorgan law.
$\lnot{(A\land B)}+\lnot{(\lnot{A}\land B)}$
Thank you.
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What have you tried? – 79037662 Oct 17 '19 at 20:45
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I solved it using a truth table, it simplifies to $\lnot{(A \land B)}$. I'm asked to solve it using DeMorgan law. – John Oct 17 '19 at 20:52
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1But it simplifies to True. – Peter Foreman Oct 17 '19 at 21:16
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Present for the day:
$\overline{AB}+\overline{{\bar A}B} = \bar{A} + \bar{B} + A + \bar{B} = A + \bar{A} +\bar{B}= 1+\bar{B} = 1$
copper.hat
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Thanks for the solution. I got that too, but since I got the solution from my Professor, saying that the expression simplifies to ¬(A∧B), I thought my solution was wrong. – John Oct 18 '19 at 04:11
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