How can I calculate this limit?
$$\lim _{(x,y) \to (0,0)} \frac{\vert{x\vert\vert{y}\vert}}{x^2 +y^2}$$
I don't have idea and I will be appreciate for your help.
How can I calculate this limit?
$$\lim _{(x,y) \to (0,0)} \frac{\vert{x\vert\vert{y}\vert}}{x^2 +y^2}$$
I don't have idea and I will be appreciate for your help.
Suppose $\;x=0\;$ , then the limit is clearly zero, but if $\;y=x\;$ then
$$\frac{|x||y|}{x^2+y^2}=\frac{x^2}{2x^2}=\frac12\xrightarrow[x\to0]{}\frac12$$
Thus, the limit doesn't exist.
Go polar to obtain
$$\frac{\vert{x\vert\vert{y}\vert}}{x^2 +y^2}=\vert{\cos \theta\vert\vert{\sin \theta}\vert}$$