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I am going to sit for UEC exam and I am 15 years old and I need helps.

The question is as follow:

If p:q:r=3:5:7 and p+q=56
Find the value of p+q+r

Thank you

  • 4
    What have you tried? What do you know about the relation between $p$ and $q$? – saulspatz Oct 23 '19 at 15:25
  • This seems fairly straightforward with a cursory understanding of ratios and it might be helpful to better articulate where you are stuck. Not trying to patronize, but if you don't understand ratios it might be helpful to be explicit about that. – Kitter Catter Oct 23 '19 at 15:28
  • Hint: Let $p=3x,q=5x,r=7x$ , then $p+q\cdots$ – 19aksh Oct 23 '19 at 15:29

2 Answers2

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Hint: From our starting equation we get $$p:q=3:5$$ so $$p=\frac{3}{5}q$$ and $$q+\frac{3}{5}q=56$$ Can you finish?

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Using ratios, $\frac{3q}{5}=p$ so replace $p$ by its expression in terms of $q$:

$\frac{3q}{5}+q=56$ which gives $q=35$ and so $p=21$ and using the ratios given, $r=49$.

So $p+q+r=21+35+49=105$