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Let $\phi$ be an eigenfunction of the Laplacian $\Delta$ on the $n$-torus $T^n$, with eigenvalue $-\lambda$, i.e. $\Delta \phi + \lambda \phi =0$, then :

$$ \phi (x)= \sum_{|n^2|=\lambda} \hat{\phi} (n) e^{in \cdot x}.$$

Why can we write $\phi$ this way?

Sara
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  • Wierdly enough, I posted a related question an hour ago. I believe the link in the beginning of my question might help you. – PML Mar 25 '13 at 22:40
  • Oh sorry, I forgot to add the link. Here it is. Hope it helps. – PML Mar 25 '13 at 22:52

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