We can assume that for every $a, a=x$, in which $x$ is anything including nothing or something. If $a\neq x$ then $a$ doesn't exist.
$a=x$ given
$x=a$ symmetry
$a=a$ transitive
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Welcome to Mathematics Stack Exchange. Reflexive means $a=a$ for all $a$ – J. W. Tanner Oct 30 '19 at 00:01
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So you are so that for any $a$ such and $\sqrt 5$ and $27$ and $-3$ then $a = x$ where $x$ can be anything including $19$ or $57$. Superman's Underwear. SO if $42 \ne \sqrt{-59}$ that can only happen if $42$ does not exist..... Are you sure this is what you want to claim? – fleablood Oct 30 '19 at 00:06
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2Reflexive: Means for all $a$ then $a=a$. Symmetric: Means whenever $a=b$ then $b =a$. And Transitive: means whenever $a=b$ and $b=c$ then $a =c$. .... what you wrote "We can assume that for every a, a=x, in which x is anything including nothing or something. If a≠x then a doesn't exist" makes utterly zero sense. – fleablood Oct 30 '19 at 00:09