0

Would somebody,please, explain to me the following notation: $$\sigma_{xx}+d\sigma_{xx}=\sigma_{xx}+(\partial\sigma_{xx}/\partial x)\,dx. $$

I do not understand how $d\sigma_{xx}$ transforms to partial $(\partial\sigma_{xx}/\partial x)\,dx.$

Thank you in advance.

Sergey

Adrian Keister
  • 10,099
  • 13
  • 30
  • 43

1 Answers1

0

If $\sigma_{xx}$ depends only on $x,$ then the equation $$\frac{\partial\sigma_{xx}}{\partial x}=\frac{\mathrm d\sigma_{xx}}{\mathrm dx}$$ is true, and what they've done is simply make a substitution of differentials.

Allawonder
  • 13,327