How do I prove the following:
$\operatorname{Pr}(A \cup B \cup C) = \operatorname{Pr}(A) + \operatorname{Pr}(B) + \operatorname{Pr}(C) $ $\qquad − \operatorname{Pr}(A \cap B) − \operatorname{Pr}(A \cap C) − \operatorname{Pr}(B \cap C) + \operatorname{Pr}(A \cap B \cap C)$?
$\max( \operatorname{Pr}(A), \operatorname{Pr}(B)) \leq \operatorname{Pr} (A \cup B)$