Write minimum 10 elements from the set $A$ defined recursively as follow
$$\begin{cases} {1\in A, 2\in A, 3\in A}\\ {x+6\in A, x\in A}\end{cases}$$
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You mean that $A$ is the smallest set with $1,2,3\in A$ and with $x+6\in A$ whenever $x\in A$? To begin with, try to find a few more elements that must belong to $A$. Then argue why no other small elements are $\in A$. – Hagen von Eitzen Nov 07 '19 at 19:00
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This is unclear, but if it says what I think it says, for any element in the set, $x+6$ in the set. – Rushabh Mehta Nov 07 '19 at 19:00
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@ Hagen von Eitzen: please tell me how it is solved in detail so i can then make similar examples myself – brisk tuti Nov 07 '19 at 19:13