In the fundamental theorem of calculus part 2 we have $$\int_a^bf(x)dx=F(b)-F(a)$$ where $F(x)$ is any anti derivative of $f(x)$ on $[a, b]$ but i want to know that what will happen if the equality $F'(x)=f(x)$ does not hold at some point in $[a, b]$ or if $F(x)$ is continuous but not differentiable at a point in $[a, b]$
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Until you learn about Lesbague Integration, assume that $f(x)$ is at least piecewise continuous. If $f(x)$ has a jump discontinuity, then $F'(x)$ will not be defined at the jump but will be defined elsewhere. – Doug M Nov 14 '19 at 09:18
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Can you give an example? – Pranava Priyanshu Nov 14 '19 at 09:20
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Can you give an example?? – Pranava Priyanshu Nov 14 '19 at 09:23
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Then you break the limits into two parts. Suppose that point is $p$ Then the new equation would be: $$\int^{y}_{x}f(x)dx=\int^{y}_{p}f(x)dx+\int^{p}_{x}f(x)dx$$
Example: Since, $f(x)=|sin(x)|$ cannot be differentiated at $\pi/2$. So, $$\int^{pi}_{0}|sin(x)|dx=\int^{pi}_{\pi/2}-sin(x)dx+\int^{\pi/2}_{0}sin(x)dx$$
Naman Jain
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