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This has been bothering me a lot, this is my thinking:

$3\dfrac12 \implies \dfrac72 \implies \dfrac{35}{10}$

similarly $\dfrac45 \implies \dfrac{8}{10}$

So

$$\dfrac{\dfrac{35}{10}}{\dfrac{8}{10}}=\dfrac{35}{8}=4.375$$

but... 35 % 8 = 3 ; 3/10? What's wrong with 4 and 3/10?

Do you ALWAYS just discard the denominator in division, is that where I'm failing?

dustin
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4 Answers4

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I don't know if I understand your question, but for any numbers $a$, $b$, and $c$, it is true that $$\frac{a/c}{b/c}=\frac{a}{b}$$ (as long as neither $b$ nor $c$ is zero, so that we're not dividing by zero anywhere).

Zev Chonoles
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35 div 8 is 4, 35 mod 8 = 3, so the answer is $4 + 3/8$ (not $4 + 3/10$).

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    This is the explanation they're looking for in terms I very much doubt they'll understand. Why not just say something like "the remainder of 3 means 'and three eighths' since you're dividing by 8, not 'and three tenths'." – Mark S. May 18 '13 at 15:32
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$$ 3.5=\frac{7}{2}\Longrightarrow \frac{7}{2}\div\frac{4}{5}=\frac{7}{2}\cdot\frac{5}{4}=\frac{35}{8}= 4\small{\frac{3}{8}}$$

DonAntonio
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First, turn it into a multiplication problem by putting in the reciprocal of the second fraction: $3$$1\over 2$$\times$$5\over 4$. Now write the mixed number as an improper fraction: $7\over 2$$\times$$5\over 4$. Now multiply the numerators and the denominators together to get the result: ${7\times 5}\over{2\times 4}$, which evaluates to $35\over 8$. You can write this as a mixed number as $4$$3\over 8$, which can be written as a decimal as $4.375$, and that's why you get it.