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I am not sure on how to start this problem. I just need a little help in starting the problem and I am certain that I can solve it, but I'm stumped on how to start. Any suggestions?

Andrew Chin
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P1081
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1 Answers1

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Using the hint, we know that $x/20=(12-y)/12$ (Because the triangles are similar) $\Leftrightarrow$ $x=20-(5/3) y$

We want the maximum value Area, which is ${x}{y}\ $, or $20y-(5/3)y^2$, so we differentiate and equal to $0$.

$\frac{d}{dy}(20y-(5/3)y^2)=0 \Leftrightarrow y = 6\ $. Plugging it in the previous formula we get that the maximum value of the area is $60$ and the minimum is obviously $0$.

RicardoMM
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