Was my attempt to solve this correct? $$\frac {\partial}{\partial a}\int_0^{\infty}r^2e^{-2ar-2br^2}dr=-2\int_0^{\infty}r^3e^{-2ar-2br^2}dr$$
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It seems correct to me. – Matha Mota Dec 22 '19 at 05:03
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1@MMM Thanks a lot. – Wisdom Dec 22 '19 at 05:03