I need help solving this problem. I think it involves Rouche's Theorem but I am not sure.
Determine the number of zeros of the function in the upper half plane. $f(z)=z^4+3iz^2+z-2+i$
I need help solving this problem. I think it involves Rouche's Theorem but I am not sure.
Determine the number of zeros of the function in the upper half plane. $f(z)=z^4+3iz^2+z-2+i$
so in you case we have
$f(z)=z^4+i(3*z^2+1)+z-2$
upper half plane as i said is that iamginary part is positive,but first let say that we can conclude we may have two function like first $f(z)=z^4+z-2$ and $g(z)=i(3*z^2+1)$
or we could say that we have tree function
$f(z)=z^4$
$f_1(z)=i(3*z^2+1)$
$f_2(z)=z-2$
if we measure this inside simple controur for example when $|z|=1$ then we may have
$|f(z)|=1$
$f_1(z)=4$
$|f_2(z)|=-1$
so we are taking positive and minimum right because of this pdf file http://fbhs.snnu.edu.cn/kcwz/all/dianzijiaoan/chn7/7.9.pdf
so it should be $1$
or in case of two function if we concatenate first two function we will get $5$,so i think it should be for two function $5$