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I was looking for an example of two dependent random variables in which
$\mathbb E(X|Y)=\mathbb E(X)$

I found this example:
$X∼U[−1,1]$ and $Y=X^2$


How can I prove that $\mathbb E(X∣Y)=0$?

thanks!

TheHolyJoker
  • 2,040

2 Answers2

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$E(XI_{{X^{2}} \leq x})=0$ for each $x$ because $X$ has same distribution as $-X$. This implies that $E(XI_A)=0$ for any $A \in \sigma (Y)$ and hence $E(X|Y)=0$.

  • Thanks for your quick answer!! I can understand why in each symmetrical section the expectation of X is zero, but why E(X|Y)=0 also? Maybe I missed something.. – Nofar Piri Jan 10 '20 at 08:38
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Hint: $E(X|X^2) = E(-X|X^2) = -E(X|X^2)$