Could someone please example how
$(\bar A . \bar B . \bar C) + (\bar A . \bar B . C) + (A . B . \bar C) + (A . B . C)$
can be simplified to
$(\bar A . \bar B) + (A . B)$ ?
Here's what I've tried, but I don't trust all the steps:
$(\bar A . \bar B . \bar C) + (\bar A . \bar B . C) + (A . B . \bar C) + (A . B . C)$
$(\bar A . \bar B . \bar C) + (A . B . \bar C) + (\bar A . \bar B . C) + (A . B . C)$
$\bar C . ((\bar A . \bar B ) + (A . B)) + C . ((\bar A . \bar B) + (A . B))$
$(\bar C + C) . ((\bar A . \bar B ) + (A . B) + (\bar A . \bar B) + (A . B))$
$(\bar A . \bar B ) + (A . B) + (\bar A . \bar B) + (A . B)$
$2 . (\bar A . \bar B ) + 2 . (A . B)$
Now I'm stuck. Am I right so far? If so, why can I cancel those $2$s?