Suppose we make a $\$100$ deposit at $t=0$ . A year later, you make a withdrawal of $\$50$. If we have an annual simple interest rate of $10\%$, what is the accumulated value at $t=2$?
Well, obviously, at the end of a year we have $\$100\times1.10 = \$110 $ and if we withdraw $\$50$, then we have $\$60$ and finally at $t=2$ we have $\$60\times1.10$ which gives $\$66$.
However, I don't understand why the solution key gives $\$65.46$.
Am I missing something?