Trigonometric differentiation

Question

I haven't use derivatives in a long time and I'm having some difficulty remembering them. Can someone explain the derivative below?

$\frac{d}{dt}\sin\theta(t)= \frac{d(\sin\theta)}{d\theta}\frac{d\theta}{dt}$

What rule is applied here?

Well, it's nonsense as you typed it. Presumably you meant to type $$\frac{d(\sin\theta)}{d\theta}\frac{d\theta}{dt}.$$ — Ted Shifrin, Jan 18 '20 at 01:41

score 1 · Accepted Answer · answered Jan 18 '20 at 01:18

1

As was stated in the comments, this is an example of the chain rule.

The chain rule states:

$$F'(x) = f'(g(x)) g'(x)$$

In this case, $\sin(\theta)$ would be $f$ and $\theta(t)$ would be $g$

answered Jan 18 '20 at 01:18

N. Bar

1 Answers1