If I have a formula $a \vee b\vee True $
What's the number of states where this is true ?
Does the W even matter? Or is it for cases where
a and b are 0 and the whole function is true, due to the W ?
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1It is always True, i.e.a tautology. Check it with the truth table for $\lor$. – Mauro ALLEGRANZA Jan 21 '20 at 17:11
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So $(x \vee y \vee z \vee w) \wedge (x \vee y \vee z \vee \neg w)$ Would be a contradiction? – Rapiz Jan 21 '20 at 17:32
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No; it is enough that one of $x,y,z$ is True. You have to review the basic def: tautology, contradiction,... – Mauro ALLEGRANZA Jan 21 '20 at 17:35
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Ah yes. But the part $(w \wedge \neg w)$ becomes irrelevant in general, due to the fact that this or part can not become true? – Rapiz Jan 21 '20 at 17:38
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1: What's W? 2: Make a truth table – xxxxxxxxx Jan 22 '20 at 20:51