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The function that has been approximated with a Taylor Series is:

$$f(x) = \frac{log(x) - x + 1}{(x-1)^2} $$

It resulted in: $$f(x) = \sum_{n=2}^{\infty} \frac{(-1)^{k-1}}{k} (x-1)^{k-2}$$

I know truncation error is:

$E = f(x) - T_n (x)$

From this, I want to construct an expression that bounds the truncation error, assuming n > 2, for a given value of x.

How does one do this with a Taylor series approximation? Do you use Taylor remainders?

1 Answers1

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You could use a geometric series as majorant, $$ |f(x)-T_m(x)|\le\frac1{m+1}\sum_{n=m+1}^\infty |x-1|^{n-2}=\frac1{m+1}\frac{|x-1|^{m+1}}{1-|x-1|}. $$

Lutz Lehmann
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