1

Let the point be (h,k)

Therefore $$2h+k=4$$ and $$hx+ky=1$$

How do I solve further? Are these lines coincident? If so, why?

Nick
  • 1,231
Aditya
  • 6,191
  • 2
    y^1 are you sure? you mean y^2? – Saketh Malyala Jan 26 '20 at 06:20
  • Which point to you mean? The common intersection that you’re meant to find can’t lie on the given line since you can find a point on it for which the chord of contact is parallel to the line. – amd Jan 26 '20 at 06:41
  • I think your question is wrong.there is no such a circle like y^2+x^1=1 as i think you observe y^2+x^2=1 – jvj Jan 26 '20 at 06:52
  • 1
    https://www.toppr.com/ask/question/the-chords-of-contact-of-the-pair-of-tangents-drawn/ – lab bhattacharjee Jan 26 '20 at 07:01

1 Answers1

1

The thing you are missing from any external point (X1,Y1) if tangents are dran to the circle X^2 + Y^2= 1 , this equality holds good XX1 + YY1 = 1. Hope this helpsenter image description here

Kartik Bhatia
  • 512