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I have proven that if $ d $ and $ \rho $ are two equivalent metrics on a set $ E $ then these metrics define the same open sets in both metric spaces $ (E, d) $ as $ (E, \rho ) $. What I tried was that every open set in $ (E, d) $ is also an open $ (E, \rho) $ and each open set in $ (E, \rho) $ is also an open $ (E, d) $.

But I can not prove the above result for closed sets. How can I prove that each closed at $ (E, d) $ is closed in $ (E, \rho) $ and vice versa?

leo
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    If you've already proven that the open sets coincide, then it's easy. For a set is closed iff its complement is open. – Alex Provost Apr 06 '13 at 18:57

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In other words: $U$ closed in $(E,d) \iff E-U$ open in $(E,d) \iff E-U$ open in $(E,\rho) \iff U$ closed in $(E,\rho)$.

Alex Provost
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