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$$ [x+(xy)]·[x + (x'y)]$$

My current belief is that it would be $0$ or $1$

but please correct me if I'm wrong

lioness99a
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DanS
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    Why is that your belief? If you explain that, then more people are likely to help you understand whether you are right or wrong – lioness99a Feb 06 '20 at 15:42
  • Yes, please describe your conclusion/belief. Note, you seem to believe it is either a tautology, or a contradiction. Which one? – amWhy Feb 06 '20 at 15:45
  • Indeed it is, @Parcly. But answers like "x" in a comment aren't helpful. Clearly the OP took a guess. I would have already answered with a derivation, had OP included work and/or reasoning. – amWhy Feb 06 '20 at 15:51
  • There are only 4 possible sets of values for $x$ and $y$. It is only a few seconds work to figure out what the value is for each of those sets. Stop working on "belief" and see what actually happens. – Paul Sinclair Feb 07 '20 at 03:25

1 Answers1

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\begin{align}[x + (xy)].[x + (x'y)] &=[x.(1 + y)].[x + y] \\&=[x].[x + y]\\&=x + x.y\\&=x . (1 + y)\\&=x\end{align}

Kaushal Doshi
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