To prove $p\iff q$ when $p$ is true, do I only have to show $q$ must be true?
Since $p$ is true, the only possible cases are '$p$ is true and $q$ is true' and '$p$ is true and $q$ is false'. So I only have to show $q$ must be true. Is that correct?
To prove $p\iff q$ when $p$ is true, do I only have to show $q$ must be true?
Since $p$ is true, the only possible cases are '$p$ is true and $q$ is true' and '$p$ is true and $q$ is false'. So I only have to show $q$ must be true. Is that correct?