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To prove $p\iff q$ when $p$ is true, do I only have to show $q$ must be true?

Since $p$ is true, the only possible cases are '$p$ is true and $q$ is true' and '$p$ is true and $q$ is false'. So I only have to show $q$ must be true. Is that correct?

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Yes. Here is the truth table:

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Here is a formal proof:

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