Here is the problem:
"A ring of mass $3\,\text{kg}$ is at rest on a rough horizontal wire. It is attached to a string that is at an angle of $60^\circ$ above the horizontal. The coefficient of friction between the ring and the wire is $0.7.$ Find the set of values for the tension, $T,$ which will allow the ring to remain in equilibrium."
So I tried using the equation that frictional force equals the horizontal component of the tension of the string acting on the ring. (Used the condition for limiting equilibrium.)
I found the expression for normal force to be, $R=30-T\sin(60^\circ).$ And formed the equation, $T\cos(60^\circ)= R(0.7).$ The tension from this equation is about $198\,\text{N}.$
However this is only one part of the solution. They asked for a set of values. The real answer is : $34.6\le T\le 198.$
Help would be appreciated, thank you.