I have a function $f(x-a,y-b\frac{1}{g(x,y)})$. I want to find the partial derivative of this function with respect to $x$. But I am literally lost. Can you give me any insight on the solution?What I could do so far is as follows: $$\frac{\partial f}{\partial x} = \frac{\partial f}{\partial g}\frac{\partial g}{\partial x}$$ I am stuck at the point in calculation of $\frac{\partial f}{\partial g}$. Thanks in advance. Have a nice day!
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Do you know what is the function $f$? – Vincent Feb 29 '20 at 17:24
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Is is actually an image. – starhd Feb 29 '20 at 21:25
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What do you mean? – Vincent Feb 29 '20 at 21:30
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The function is an image. $f(x,y)$ is the function of an image – starhd Feb 29 '20 at 22:00
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I'm not sure I understand what you mean. So you don't have any expression for $f(x,y)$? – Vincent Feb 29 '20 at 22:07
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It is exactly the case! – starhd Feb 29 '20 at 22:21