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I am confused by a discussion with a colleague. The discussion is about the period of a periodic function.

For example, the periodic function $$f(x)=\sin(x), \quad x\in (0,\infty)$$ has period $2\pi$. If I change the scale and build the function, $$g(x)=\sin(\ln x),\quad x\in (0,\infty)$$ is this new function, g, periodic? If it is, what is the period?

EDIT

I will clarify my point. If I change the scale of the function $g$, let's say, $\ln x =u$ then I will have function $$h(u)=\sin u, \quad u\in \mathbb R$$ and now $h$ is periodic on $u\in \mathbb R $.

So, my point is can I say that $g$ is not periodic in $x$-domain but it is in $\log$-domain?

Arnaldo
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2 Answers2

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$g$ is not periodic as the difference between two consecutive roots is unbounded as we consider the roots going to $\infty$.

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Functions such as $\sin(\ln x)$ are called log-periodic rather than periodic.

J.G.
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  • It was just a example, I could write $g(x)=\sin (e^x)$ and the ask the same question. What do you think? – Arnaldo Mar 02 '20 at 12:36
  • @Arnaldo While I've encountered no discussion of such functions, it would make sense to call them something like exp-periodic. Again, though, it's not periodic, because no constant $p$ satisfies $\sin e^x=\sin e^{x+p}$ for all $x$. – J.G. Mar 02 '20 at 12:42