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I have the expression $$e^{log(3)* log(7)\over log 2}$$

I know it can be simplified to $$3^{log(7)\over log(2)}$$ But I don't know how its done.

2 Answers2

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HINT $$e^{k \log(a)} = \left(e^{\log(a)} \right)^k = a^k$$

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Use the fact that

$$e^{b \log{a}} = a^b$$

Ron Gordon
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