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Find $f '(0)$ for the function \begin{align} f(x)=\begin{cases} \frac{g(x)}{x^2}, & \text{if }x \not = 0\\ 0, & \text{if }x=0 \end{cases} \end{align}

With \begin{align} g(0)=g'(0) = g''(0) = 0 \\ g'''(0) = 14 \end{align}

Thomas
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2 Answers2

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Hint: Think of $$f'(0)=\lim_{x\to 0}\frac{f(x)-f(0)}{x-0}$$

Mikasa
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  • Nice hint - my you've grown an impressive beard :-) +1! – Amzoti Apr 13 '13 at 05:12
  • Hello, dear friend! I hope to cross paths soon! +1 – amWhy Apr 14 '13 at 01:17
  • @Amzoti: He is Gandalf. Gandalf is a character and you know him if you see the movie called Hoobit! – Mikasa Apr 14 '13 at 05:10
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    @BabakS.: Yes, I actually like him as he has excellent wisdom, street smarts and knows just how much to help! The video comes out soon of the latest movie. Hope all is well and good to see you around as usual! – Amzoti Apr 14 '13 at 05:12
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Hint: Use the definition and L'Hôpital's rule.

The answer is $\dfrac pq$ with $p,p-q\in\{7,1,8,6,4\}$.

P..
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