Is this boolean answer correct?

Question

F(x,y,z) = (x + y')(x + y)(xz')
= (xx) + (xy) + (xy')+(y'y)(xz')
= [x + (xy) + (xy') + 0 ] (xz')
= [x + x(y + y') + 0] (xz')
= [x + x(1) + 0] (xz')
= [x + x + 0] (xz')
= [x + x] (xz')
= x*(xz')
= (xx)*z'
= xz'

xz' is my final answer.

$(xz')$ should be a factor in all the terms after you distribute. — paw88789, Mar 11 '20 at 14:04

score 0 · Accepted Answer · answered Mar 11 '20 at 20:01

0

Well yes, $$(x+y^\prime)(x+y)=x$$ and $$x(xz^\prime) = xz^\prime,$$ so your result is correct.

answered Mar 11 '20 at 20:01

mjw

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Is this boolean answer correct?

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