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Let me refer you to:

http://www-users.math.umd.edu/~karpuk/chap3solns.pdf

Page 2, ex. 4

Can you please explain the following step:

$tb=f(s')b=s'b$

Why $f(s')=s'$ ?

Thanks

user6495
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1 Answers1

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Hint: We have a map $f:A\rightarrow B$. This makes $B$ into an $A$-module. What is the definition of "$ab$", for $a\in A$ and $b\in B$?

Zev Chonoles
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