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$ABCD$ is a parallelogram. $\triangle CDE$ is an isosceles triangle. $\angle DAB \text{ is } 64^°$. Work out the size of the $\angle DEC$.

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amWhy
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Jess STAZICKER
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1 Answers1

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By the proprieties of parallelogram, we have: $$\angle BAD=\angle CDE$$ Now because $CDE$ is isoscele, we have: $$\angle CED=180°-2\cdot \angle CDE = 180°-2\cdot64°=52°°$$

Matteo
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