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If 5 cards are randomly selected from a standard deck of cards with replacement, what's the probability of getting at least 1 red queen?

Here's what I've done but I'm unsure if it's right, here I'm assuming this is a binomial distribution:

$$Y\sim Bin(52,\frac{1}{26})$$ $$1-P(Y=0)=1-{52\choose 0}*\frac{1}{26}^0*\frac{25}{26}^{52}$$

I'm sure if the number of trials should be $5$ or $52$. Please help me with this. Thank you

user672518
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    It is not $52$ trials, it is $5$. – GEdgar Apr 02 '20 at 12:23
  • To get insight into the formula, suppose you only drew one card. Clearly the answer in that case is $\frac 2{52}$, yes? So your formula has to return that value. – lulu Apr 02 '20 at 12:32

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