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It is like starting the summation of the Harmonic Series but from the "end".Could we say that when $\lim_{k\to \infty}$ $\sum_{i=1}^{k} \frac{1}{k+1-i}$ is equal to the Harmonic Series?

sliiime
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1 Answers1

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$\sum_{i=1}^k\frac1{k+1-i}=\sum_{j=1}^k\frac1j$ for all $k$, therefore your $k$-th term is the $k$-th harmonic number.