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The Problem

I thought the acceleration would be cosx at x= pi/6, but that’s the wrong answer! Can someone help me here? It’s question three.

Flinn Bella
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  • It's homework, and we have unlimited attempts on it. I've already tried to solve this problem two other times. I'm pretty sure I put in .866 both times... – Flinn Bella Apr 23 '20 at 11:13

1 Answers1

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Hint: Chain rule.

$t$ for time; $a$ for acceleration.

$a=dv/dt=(dv/dx)(dx/dt)$

Peter Szilas
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  • But why would that differ from just finding the derivative of the velocity function? – Flinn Bella Apr 23 '20 at 11:29
  • $a=\frac{dv}{dt}$ so you need to use the chain rule in the context of implicit differentiation like the answer suggested.the independent variable here is time – Saif DOGHRI May 09 '20 at 15:16