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\begin{bmatrix}1 & h& h^2 & 1\\ h^2 & h & 1 & 2\\h & h^2 & 1 & 1 \end{bmatrix}

Given the matrix above is an augmented matrix, what is the possible value h where there is no solutions, unique solutions, and infinite solutions?

I have tried

1) reducing the matrix to \begin{bmatrix}1 & h& h^2 & 1\\ 0 & h-h^2 & 1-h^2 & 1-h^2 \\ 0 & 0 & 1-h^3 & 2-h \end{bmatrix}

2) For infinite soloution $$1-h^3 = 2-h$$ $$h^3-h+1 = 0$$

3) For no solution $$ 1-h^3 = 0$$ $$ h = 1$$ $$ h -2 = 0 $$ $$h = 2$$

4) For unique solution $$ h\neq 1,2$$

I am a bit unsure of whether my solution because it seems weird for my answer of infinite solutions.

winson
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  • Yes, there is something wrong. Consider $h=1$. Then we have infinitely many solutions. But you require $h^3-h+1=0$, which is not satisfied by $h=1$. – Dietrich Burde May 06 '20 at 11:08
  • Are you sure you did that row-reduction correctly? It doesn’t look at all right. – amd May 06 '20 at 20:28

0 Answers0