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For complex valued function $x(n)$, is $|x(n)|^{2} = x(n)^{2}$?

This is briefly described in formula for square of absolute value of difference of two variables |a−b|2, but no further details are given

Jan
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1 Answers1

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Not in general, take $x(n) \equiv \mathrm i$. Then $\lvert x(n) \rvert^2 = 1$, but $x(n)^2 = -1$.

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