A counter-example (based on my misunderstanding) is, say, if $(-3)^3=-27$ then why is it not the case that $log_{-3}(-27)=3$?
Asked
Active
Viewed 30 times
1
-
The base of a logaritm is $a>0, a\neq 1$. In addition the argument is always $>0$. – Sebastiano Jun 01 '20 at 20:35