$$AB'C'D+ABCD$$ $$=AD(B'C'+BC)$$ $$=AD$$
I have simplified this expression right but for some reason I still get the answer wrong. The expression $AD$ does not match the original truth table. Please help.
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The thing is though $B'+B=1$ and $C'+C=1$, but $B'C'+BC\ne 1$ for $B=0,C=1$ and $B=1,C=0$ – Alexey Burdin Jun 08 '20 at 07:48
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Note that $B'C' \ne (BC)'$
$$AB'C'D + ABCD = AD(B'C' + BC) = AD((B+C)'+BC)$$
Aniruddha Deb
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